I was in bed trying to get to sleep but my brain wanted to know the answer to this question. So I was forced out of bed to write this experiment:
function main( $argv ) { register_shutdown_function( 'shutdown_1' ); register_shutdown_function( 'shutdown_2' ); exit( 0 ); } function shutdown_1() { exit( 1 ); } function shutdown_2() { exit( 2 ); } main( $argv );
With this PHP code, what do you expect is the resultant error level?
The answer is ‘1’. After main() calls exit( 0 ) the shutdown function shutdown_1() is invoked. When shutdown_1() calls exit( 1 ) the process exists and shutdown_2() is never called.
I’m glad we cleared that up. Back to bed.