In this photo we see three voltmeters (across the top) and five ammeters (across the bottom) attached to a voltage divider connected to a load.
30 V is applied then 2 mA flows through R1 and then splits with 1 mA going through R2 and 1 mA going through Rload. 20 V drops across R1 and there is 10 V across R2 and Rload.
The circuit on the left in the schematic below is the one being tested. In this case R1, R2, and Rload are all 10 kΩ. As R2 and Rload are connected in parallel their effective resistance is 5 kΩ. R1 being 10 kΩ gets two thirds of the voltage because R2 || Rload is 5 kΩ getting one third of the 30 V being 10 V.
I asked Tony359 about his current limiter and he referred me to the video below in which he explains his home made contraption. Very cool. I think I should make one of these.
Update: I also found a video covering a similar topic:
I was doing some prep work for the upcoming LAoE video and learning about Thevenin equivalent circuits, something I need to understand better than I do, particularly how to calculate Vth and Rth. I built the circuit on my bench, but then got readings I didn’t understand, so I asked about it over on the EEVblog Forum: Help with Thevenin equivalent circuit. In the end it turned out that my initial readings were wrong for some unknown reason, but when I repeated them they came out right the second time…
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Thanks very much for watching! And please remember to hit like and subscribe! :)
p.s. today I added Rigol and Imager to my spell check.
Following is a product I use picked at random from my collection which may appear in my videos. Clicking through on this to find and click on the green affiliate links before purchasing from eBay or AliExpress is a great way to support the channel at no cost to you. Thanks!
Thanks very much for watching! And please remember to hit like and subscribe! :)
p.s. today I added to my spell check.
Following is a product I use picked at random from my collection which may appear in my videos. Clicking through on this to find and click on the green affiliate links before purchasing from eBay or AliExpress is a great way to support the channel at no cost to you. Thanks!
